What is the maximum acceleration a truck can have without a box sliding forward?

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The maximum acceleration a truck can have without a box sliding forward is determined by the relationship between static friction and the forces acting on the box. The equation f_s = μn = μmg defines the static friction force, where μ is the coefficient of static friction and n is the normal force. To prevent the box from sliding, the maximum deceleration of the truck must equal the static friction force acting on the box. Thus, the maximum acceleration (a) can be expressed as a = -μg, where g is the acceleration due to gravity.

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1. A person driving a truck has a box in the back. They are driving at a constant speed (v_0) when they notice a red light and have to stop. What is the maximum acceleration the truck can have without causing the box to slide forward? (Answer must be given in terms of variables, as no values are given)



2. Sum of forces in the x direction=m*a, f_s=[tex]\mu[/tex]*n= [tex]\mu[/tex]*mg.



3. The thing that confuses me most is the acceleration. I assume the acceleration is negative because the truck is slowing down. I don't understand what force is acting on the box to slide it forward (I know friction is pushing it back), or how to measure that force. I assume f_s has to equal that force so the box doesn't move, but if it does, the sum of forces = 0, and thus m*a=0, thus a=0. But a can't be zero! So how do I solve for a?
 
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The net force is zero and the net force is not just ma. You stated that you knew that the static friction force must be equal to the maximum stopping force. Can you set up an equation that will allow you to solve for acceleration now?
 

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