What Is the Maximum Angular Momentum of a Particle Moving Past a Point?

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SUMMARY

The maximum angular momentum of a particle moving past a point O occurs when the particle's distance from the point is perpendicular to its velocity. Given a mass of 2 kg and a velocity of 3 m/s, with a minimum distance of 2 m from point O, the angular momentum can be calculated using the formula L = m * v * r, where L is angular momentum, m is mass, v is velocity, and r is the perpendicular distance. Thus, the maximum angular momentum is L = 2 kg * 3 m/s * 2 m = 12 kg·m²/s.

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dinonichas
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Homework Statement



A particle moves in a straight line past a point O, as shown below. At which point is the angular momentum maximum (with respect to O)? If the minimum distance between O and the line is 2 m, and the object has a mass of 2 kg and a velocity of 3 m/s, what is the maximum angular momentum of the particle with respect to O?


Homework Equations



angular momentum is equal to:
Iω= (mr^2)mv ??

The Attempt at a Solution



0,i think,because the momentum should be 90 degree from the radius to make the angular momentum.so in this case the particle is moving in the straight line with the point O so it will be 0
 
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dinonichas said:
angular momentum is equal to:
Iω= (mr^2)mv ??

[tex]\omega \neq mv[/tex]

There is a simple formula relating angular momentum to mass, velocity, and radius vector. Find that formula in your textbook and use it.

the momentum should be 90 degree from the radius to make the angular momentum.

This is correct.

so in this case the particle is moving in the straight line with the point O so it will be 0

But this isn't. If the point O is 2 m from the line, the angular momentum (with respect to that point) can't be zero.
 
Last edited:

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