What is the Maximum Energy and Velocity in Spring Oscillation?

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SUMMARY

The maximum energy stored in a spring oscillation with a 0.70 kg mass is calculated to be 3.86 x 10^-3 J. The maximum velocity of the mass during oscillation is determined to be 0.105 m/s, using the formula V_max = w*A, where w is the angular frequency (2.10 rad/s) and A is the amplitude (0.0500 m). The calculations confirm that the equations used are correct for this scenario.

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A 0.70 kg mass on a spring oscilates horizontally with a little friction acording to the
x= 0.0500 cos (2.10 t) where x is in meter and t is in seconds. Find the maximum energy stored in the spring during an oscilation. Find the maximum velocity of the mass.

V_max = w*A= (0.05)*(2.10)= 0.105 m/s

But the maximum energy E=(1/2)(m)(v_max ^2)= (1/2)(0.70)(0.105)^2= 3.86 x 10^-3 J

Is this problem correct?... or i use the wrong equations...
 
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Looks OK to me.
 

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