What Is the Maximum Error in an 8-bit ADC with a Full Scale Input of 2.55V?

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The discussion centers on calculating the maximum error in an 8-bit ADC with a full-scale input of 2.55V, factoring in cumulative errors of 2.55mV. The quantization error is identified as half of the least significant bit (LSB), which is calculated to be 10mV. When combining this with the cumulative error, the total maximum error is determined to be 12.55mV. There is a debate on whether cumulative errors include quantization error, with some arguing that it should not. Ultimately, the consensus is that the correct maximum error is 12.55mV.
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Homework Statement


An 8 bit ADC has a full scale input of 2.55V. If other cumulative errors are 2.55mV, determine the maximum error.

Options are: 10mV, 2.55mV, 12.55mV, 7.45mV

Homework Equations


I believe this is a conceptual question. The only equation I can come up with is that the quantization error in an ADC is at max, half of LSB.

The Attempt at a Solution


Assuming cumulative errors as mentioned in the question does not include quantization error (LSB/2),
maximum error
= Q error + C error
=5mV + 2.55mV
= 7.55mV

If cumulative errors include Q error, then max error = 2.55mV as the other errors that can creep into an ADC are non-linearity and aperture errors, both of which more data to calculate.
 
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asp_physics said:

Homework Statement


An 8 bit ADC has a full scale input of 2.55V. If other cumulative errors are 2.55mV, determine the maximum error.

Options are: 10mV, 2.55mV, 12.55mV, 7.45mV


Homework Equations


I believe this is a conceptual question. The only equation I can come up with is that the quantization error in an ADC is at max, half of LSB.


The Attempt at a Solution


Assuming cumulative errors as mentioned in the question does not include quantization error (LSB/2),
maximum error
= Q error + C error
=5mV + 2.55mV
= 7.55mV

If cumulative errors include Q error, then max error = 2.55mV as the other errors that can creep into an ADC are non-linearity and aperture errors, both of which more data to calculate.

I think your solution is correct. Half of an LSB plus the other error...
 
There is no such ans like 7.55mv.
I think...
Quantization Error is (ε Max)= 2.55v/(2^8)=10 mv
so total error = 10mv+2.55mv = 12.55 mv(Correct Ans)

As per ur concept," if Qunts. error contain in 2.55mv other Cumulative error " which is not possible.

10-2.55 =7.45 mv(not the Ans)
 
Last edited:
Although you might think an ADC module should be designed to have a quantization error of ½LSB, in practice it may be the case that max quantization error = LSB. This comes about by max input (corresponding to output=11111111) being 127/128 Vref.
 

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