What is the maximum height the ball reaches

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SUMMARY

The maximum height the golf ball reaches above the level from which it was hit is calculated using the formula vf^2 = vi^2 + 2ad. With an initial velocity of 35 m/s at a launch angle of 70 degrees, the vertical component of the velocity is 35sin70. The calculation yields a maximum height of 55 meters. The initial height of 6 meters does not factor into this specific calculation, as the question explicitly asks for the height above the launch level.

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chukie
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A golfer faces an approach shot from the fairway to an elevated green 6 metres above where she stands. She uses a pitching wedge with a loft of 70 degress and the ball leaves her club traveling at 35 m/s.
What is the maximum height the ball reaches above the level from which it was hit?


What I did:
vf^2=vi^2+2ad
0=(35sin70)^2+(2*-9.8)d
d=55 m

i was just wondering if i have to take the 6 metres into account?
 
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chukie said:
A golfer faces an approach shot from the fairway to an elevated green 6 metres above where she stands. She uses a pitching wedge with a loft of 70 degress and the ball leaves her club traveling at 35 m/s.
What is the maximum height the ball reaches above the level from which it was hit?


What I did:
vf^2=vi^2+2ad
0=(35sin70)^2+(2*-9.8)d
d=55 m

i was just wondering if i have to take the 6 metres into account?
No, since the question asked:
chukie said:
What is the maximum height the ball reaches above the level from which it was hit?
There is no need to take into account the initial height. However, if the question were to inquire about the ball landing then you would need to taking into account the additional 6m.
 


thanks =)
 

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