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achilles89
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I have been looking all over the web and can find nothing...How do I calculate this? Please help if you can..thankyou
What is the maximum pressure that a %99.9 pure tungsten tube can withstand?
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SUMMARY
The maximum pressure that a 99.9% pure tungsten tube can withstand is determined by its ultimate tensile strength, which ranges from 80,000 to 500,000 psi based on various sources. The formula to calculate the maximum internal differential pressure is P = 2T·t/D, where T represents the tensile strength, t is the wall thickness, and D is the tube diameter. This calculation is crucial for applications requiring precise pressure tolerances in tungsten tubes.
PREREQUISITES- Understanding of tensile strength and its significance in materials science.
- Familiarity with the formula for calculating internal pressure in cylindrical structures.
- Knowledge of tungsten properties, specifically its purity levels and mechanical characteristics.
- Basic mathematical skills for applying the formula P = 2T·t/D.
- Research the mechanical properties of tungsten, focusing on its tensile strength variations.
- Study the application of the formula P = 2T·t/D in different engineering contexts.
- Explore the effects of wall thickness and diameter on pressure tolerance in cylindrical tubes.
- Investigate the manufacturing processes for high-purity tungsten tubes and their applications.
Engineers, materials scientists, and professionals involved in the design and application of high-pressure systems using tungsten materials.
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