What is the Meaning of dy/dx in Nonstandard Calculus?

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The discussion clarifies that dy/dx is the Leibniz notation for the derivative, representing the derivative of y with respect to x, rather than a simple division of dy by dx. It emphasizes that in the context of the equation y=x², the derivative is found using implicit differentiation, resulting in the expression 1*dy/dx=2x. Additionally, it notes that in nonstandard calculus, dy/dx can be interpreted as dy divided by dx when using infinitesimals instead of limits.

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micromass said:
It's the Leibniz notation for the derivative. See http://en.wikipedia.org/wiki/Derivative
very long article.
Actually the thing i want to ask is Does dy/dx means dy divided by dx.
 
vkash said:
very long article.
Actually the thing i want to ask is Does dy/dx means dy divided by dx.


Not at all! dy/dx is simply a notation. It's a notation for the derivative with respect to y.
 
It means the same thing as f'(x) does. Take whatever y is and take the derivative of it with respect to x.
If we have the equation, {y=x^2} what's the derivative with respect to x? We have to use implicit differentiation because you can't the derivative of y when we are taking it it with respect to x. So you have {1*dy/dx=2x}

Hopefully my explanation is clear haha.
 
It does, in some sense, mean \mathrm dy divided by \mathrm dx in nonstandard calculus, where we use infinitesimals instead of limits to do calculus.
 

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