What is the method for solving cosine squared equations?

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    Cosine Method
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To solve the equation cos²(θ) = 0.6 by hand, one approach is to take the square root of 0.6 and use cosine tables for reference. The equation can be rewritten using the double angle formula: cos(2θ) = 2cos²(θ) - 1, leading to cos(2θ) = 0.2. This can be solved by finding the angle corresponding to 0.2, resulting in θ ≈ π/4 - 0.1. A calculator check confirms the accuracy of this method.
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I was just finishing my physics homework (don't worry this isn't a HW question, the homework is done) and the last calculation I had to do was cos2(θ) = 0.6. I just plugged this into my calculator to solve for me and got it right.

Now I'm curious though. How would one solve this by hand?
 
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HunterDX77M said:
I was just finishing my physics homework (don't worry this isn't a HW question, the homework is done) and the last calculation I had to do was cos2(θ) = 0.6. I just plugged this into my calculator to solve for me and got it right.

Now I'm curious though. How would one solve this by hand?

Take the square root of 0.6 by hand, and use cosine tables?
 
HunterDX77M said:
cos2(θ) = 0.6. I just plugged this into my calculator to solve for me and got it right.
Now I'm curious though. How would one solve this by hand?
If you really mean 'by hand' (no calculator),
cos(2θ) = 2 cos2(θ) -1 = 0.2 = sin(π/2 - 2θ)
π/2 - 2θ ≈ 0.2
θ ≈ π/4 - 0.1
Check (by calculator): cos2(π/4 - 0.1) = 0.5993..
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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