Solving Cosine of 330 Degrees: Conjugate Method vs. Alternative Method Explained

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    Cosine Degrees
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Homework Help Overview

The discussion revolves around calculating the cosine of 330 degrees without a calculator, exploring different methods including the conjugate angle method and an alternative approach. Participants are examining the definitions and relationships between sine and cosine in the context of angles greater than 90 degrees.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the discrepancy between their method and the conjugate angle method used by their teacher. Some participants question the use of terms related to sine and cosine for angles larger than 90 degrees, while others suggest viewing angles in relation to the x-axis.

Discussion Status

Participants are actively engaging with the concepts, with some guidance provided regarding the relationship between sine and cosine and the importance of the unit circle. There is an acknowledgment of the periodic nature of sine and cosine functions, but no explicit consensus has been reached on the original poster's method.

Contextual Notes

There is a mention of potential confusion arising from the use of certain terms for angles greater than 90 degrees, as well as the need to consider angles in relation to the x-axis. The original poster's method and the teacher's method are being compared, highlighting different interpretations of the problem.

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Homework Statement


Cos(330 degrees)
*No calculator

Homework Equations


(a^2)+(b^2)=(c^2)
Cos=(delta x / hypotenuse)

The Attempt at a Solution


Hi guys, so today at school, the teacher was doing a problem which stated to solve the cosine of 330 degrees. The teacher used the conjugate angle method to get the answer 0.866.
However, I do not see what is wrong with my method (link to image will be below), because when I do it, I get -0.5. Please help, this has been frustrating me- I do not get why the conjugate method works, but not the one I used.
How I did it: https://imgur.com/a/Vp3ne
 
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Hammad Shahid said:
delta x / hypotenuse
You are taking ##\delta y## divided by the hypothenuse ... You are computing the sine, not the cosine.
 
Orodruin said:
You are taking ##\delta y## divided by the hypothenuse ... You are computing the sine, not the cosine.
Sorry, I meant in relation to the angle, like such: https://imgur.com/a/hdKyE

IDK, it’s something my teacher showed me last year, like tangent = (y/x), or opposite/adjacent.
 
You really should not be using those terms for angles larger than 90 degrees, it will most likely just confuse you.

What you are computing is the sine, no matter how you frame it. The easiest way to remember things is to look at the unit circle with the angle ccw from the x axis. The x value is the cosine and the y value the sine.
 
Orodruin said:
You really should not be using those terms for angles larger than 90 degrees, it will most likely just confuse you.

What you are computing is the sine, no matter how you frame it. The easiest way to remember things is to look at the unit circle with the angle ccw from the x axis. The x value is the cosine and the y value the sine.
Hmm, okay. However, wouldn’t that then technically be the same as cosine of -30 degrees?
But over here, 330-270=60 degrees.
So the only logical thing I can think of is that I have to view the angles in relation from the x-axis, Am I correct in saying that?
 
Hammad Shahid said:
But over here, 330-270=60 degrees.
So the only logical thing I can think of is that I have to view the angles in relation from the x-axis, Am I correct in saying that?
Yes. View it in relation to the x-axis.
 
Ok. Now that I think about it, it makes a lot of sense.
Thank you both of you guys.
 
Hammad Shahid said:
Hmm, okay. However, wouldn’t that then technically be the same as cosine of -30 degrees?
Yes. Both sine and cosine are periodic with a period of 360 degrees.
 

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