What Is the Minimum Time for a Sportscar to Travel 1/2 Mile from Standstill?

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SUMMARY

The minimum time required for a sportscar to travel 1/2 mile from a standstill, given it accelerates uniformly to 120 mi/h in 30 seconds and has a maximum braking rate of 0.7g, involves calculating acceleration and deceleration phases. The acceleration is determined to be 4 mi/min, leading to the equations V1 = 4t and V2 = 4t1 - 0.7gt. The integration of distance over time yields the equation d = 0.5 = int(4t, t, 0, t1) + int(4t1 - 0.7gt, t, 0, t2), which simplifies to 2t1^2 + 4t1t2 - 0.7g/2 t2^2. The challenge lies in deriving the total time t from its components t1 and t2.

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Homework Statement


a A sportscar can accelerate uniformly to 120 mi/h in 30s. Its maximum braking rate cannot exceed 0.7g. what is the minimum time required to go 1/2 mi, assuming it begins and ends at rest?


Homework Equations


I drew a graph of v(t) vs t. where the initial acc. goes up to a certain time, t1, then decelerate to a rest at t2.


The Attempt at a Solution



acc= 4 mi/min
V1 = 4t

For convenience i drew another graph for when the car dec. Therefore:

acc= -0.7g
V2 = 4t1 - 0.7gt

Integrate:

d = 0.5 = int ( 4t, t, 0, t1) + int (4t1 - 0.7gt, t, 0, t2)

=> 2t1^2 + 4t1t2 - 0.7g/2 t2^2

Here is where i got lost. i know that t = t1 + t2 but i don't know how to derive t with its components to get the minimum time. please help and thank you.
 
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Interesting problem. You can determine t2 in terms of t1 because the velocity must be zero in the end. Other considerations are less than max deceleration and coast time between acceleration and deceleration.
 
Last edited:

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