What Is the Molar Ratio of Two Ideal Gases in a Mixture?

[enokoner]

Homework Statement

A mixture of two gases, A and B, exists at pressure p1, volume V, and temperature T1. Gas A is subsequently removed from the mixture in a constant-volume process. The remaining gas B is found to have a pressure p2, volume V, and temperature T2. Express the ratio of the number of moles of gas B to the number of moles of gas A in the terms of p1, p2, T1 and T2.

a. \frac{p_2 T_1}{p_1 T_2 - p_2 T_1}

b. \frac{p_2 T_1^{2}}{T_2(p_1 T_2 - p_2T_1)}


*Options c and d were not written because they contained specific gas constants which do not pertain to molar equations.

Homework Equations

Ideal Gas: pV = N \overline{R}T

Dalton's Law: p = \sum p_i

The Attempt at a Solution

Universal gas constant crosses out. Volume stays constant and also crosses out.

∴ \frac{N_B}{N_A}= \frac{p_B T_A}{T_B p_A}


Relating p_A and p_B to p₁

p_1= p_A + p_B


and to p₂

p_2 = p_B


Also, T_A = T_1 \ T_B = T_2


∴ \frac{N_B}{N_A}= \frac{p_2 T_1}{T_2(p_2 - p_1)}


This is not an option. I have a feeling its because I assumed p_2 = p_B. That assumption doesn't feel right. I don't know how else to relate these two. Thank you for considering this.

 

[Borek]

\frac{N_B}{N_A}= \frac{p_B T_A}{T_B p_A}

I am not sure I get it.

I have a feeling you can be a victim of your own choice of confusing indices.

 

[enokoner]

I am not sure I get it.

I have a feeling you can be a victim of your own choice of confusing indices.

I agree that the indices are out of control. But I double checked. Sorry for the step-skipping.

<br /> <br /> N = \frac{pV}{\overline{R}T} \\<br /> <br /> ∴ \frac{N_B}{N_A} = \frac{\frac{p_BV}{\overline{R}T_B}}{\frac{p_A V}{\overline{R}T_A}} \\<br /> <br /> =\frac{p_B T_A}{p_A T_B}<br /> <br /> <br />

 

[Borek]

p_1= p_A + p_B

Aren't p_A and p_B measured at different temperatures?

I got 'a', starting from

p_1V=(N_A+N_B)RT_1

p_2V=N_BRT_2

 

[enokoner]

OP Second Attempt by solving in reverse.

I got the answer but I don't know how. The book states that the answer is B. I got it by solving the problem in reverse. I used a common equation that relates pressure and temperature wrt Ideal gases. The problem is I don't understand why I'm supposed to used that or why I should set certain values to each other.2.1 Relevant equationsIdeal Gas: pV = N \overline{R}T

Dalton's Law: p = \sum p_i

Assuming System is isentropic: \frac{T_2}{T_1} = (\frac{p_2}{p_1})^{\frac{k-1}{k}}


3. Second attempt at a solution

Universal gas constant crosses out. Volume stays constant and also crosses out.

∴ \frac{N_B}{N_A}= \frac{p_B T_A}{T_B p_A}Relating p_A and p_B to p₁:

p_1= p_A + p_Band to p₂:

Assuming (I HAVE NO BASIS FOR THIS ),

p_B = p_2 ; \ p_2 = p_1 ; \ k = 0.5 Therefore,

\frac{T_2}{T_1} = (\frac{p_B}{p_2})^{\frac{0.5-1}{0.5}} \\<br /> <br /> = \frac{P_2}{P_B} \\<br /> <br /> ∴ p_B = p_2 \frac{T_1}{T_2} \\<br /> <br /> ∴ p_A = p_1 - p_B = p_1 - p_2(\frac{T_1}{T_2})

Also, T_A = T_1 ; \ T_B = T_2Substituting,

\frac{N_B}{N_A}=\frac{p_2(\frac{T_1}{T_2})T_1}{T_2(p_1-p_2(\frac{T_1}{T_2})} \\= \frac{p_2 T_1^{2}}{T_2(p_1 T_2 - p_2 T_1)}I know setting those values arbitrarily is nonsense. But I thought perhaps it could give me some insight. It has not. I'm grasping at straws. Can anyone help?

 

[enokoner]

Thank you so much.

I got your same answer using your very clear setup. (You rock man). The solution was too good. It was elegant and made sense the whole way through...

Setting both eqs. equal to V/R:

\frac{N_A}{N_B}+ \frac{N_B}{N_B} =\frac{T_2 p_1}{p_2 T_1} \\<br /> <br /> \frac{N_B}{N_A} = \frac{1}{\frac{T_2 p_1}{p_2 T_1} -1} \\= \frac{p_2 T_1}{T_2 p_1 -p_2 T_1}<br />

Thats how it should be. So I went hunting for the online errata. I can't believe I didn't do this sooner!

Amazing Borek! I got to go over all the errata. Thanks a million.