What is the Most Energetic Lyman Line?

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SUMMARY

The most energetic Lyman line refers to the transition in hydrogen that emits the photon with the shortest wavelength, corresponding to the highest frequency. In this context, the energy of the emitted photon can be calculated using the formula E = hv, where h is Planck's constant. The discussion clarifies that "most energetic" is synonymous with "shortest wavelength" or "highest frequency," which is crucial for understanding the recoil shift of the hydrogen atom upon photon emission. Additionally, the conservation of momentum principle is relevant when considering the effects on the atom at rest emitting a photon.

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Homework Statement



part b) Calculate the recoil shift for the emission of the most energetic Lyman line from a free atom of hydrogen.

2. The attempt at a solution

My question isn't a physics one per se, I'm stuck on terminology. What is meant by "the most energetic Lyman line"? I'm use to thinking of Lyman series in terms of frequency, and it doesn't seem to make sense to me to try and calculate the energy from frequency in this case. Any thoughts?
 
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Use Planck's constant. If v is the frequency of the emitted photon, then the energy E=hv, where h is Planck's constant.
 
Right, which is also E = hc/lambda. I guess my sticking point is in comprehension of what I'm being asked rather that the mathematics or arithmetic.
 
Do photons carry momentum?

What does conservation of momentum say about what happens to an atom at rest which emits a photon?
 
atomicpedals said:
E = hc/lambda.
Yes, so "most energetic" is synonymous with "shortest wavelength" or "highest frequency".
 
Ah, gotcha. The fog has been lifted, thanks for the help!
 

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