What is the Most Energetic Lyman Line?

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Homework Help Overview

The discussion revolves around calculating the recoil shift for the emission of the most energetic Lyman line from a free hydrogen atom, focusing on the terminology and understanding of the concept of "most energetic Lyman line."

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the meaning of "most energetic Lyman line," with one questioning the terminology and its implications for calculating energy. Others clarify that it relates to the shortest wavelength or highest frequency of the emitted photon.

Discussion Status

The discussion has progressed with participants providing clarifications on the relationship between energy, frequency, and wavelength. There is an acknowledgment of the conceptual challenges faced by the original poster, and some guidance has been offered regarding the terminology.

Contextual Notes

Participants are navigating the definitions and implications of terms related to the Lyman series, particularly in the context of energy calculations and photon emission.

atomicpedals
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Homework Statement



part b) Calculate the recoil shift for the emission of the most energetic Lyman line from a free atom of hydrogen.

2. The attempt at a solution

My question isn't a physics one per se, I'm stuck on terminology. What is meant by "the most energetic Lyman line"? I'm use to thinking of Lyman series in terms of frequency, and it doesn't seem to make sense to me to try and calculate the energy from frequency in this case. Any thoughts?
 
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Use Planck's constant. If v is the frequency of the emitted photon, then the energy E=hv, where h is Planck's constant.
 
Right, which is also E = hc/lambda. I guess my sticking point is in comprehension of what I'm being asked rather that the mathematics or arithmetic.
 
Do photons carry momentum?

What does conservation of momentum say about what happens to an atom at rest which emits a photon?
 
atomicpedals said:
E = hc/lambda.
Yes, so "most energetic" is synonymous with "shortest wavelength" or "highest frequency".
 
Ah, gotcha. The fog has been lifted, thanks for the help!
 

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