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## Homework Statement

The 19.6 cm diameter disk rotates on an axle through its center. F1=22.8 N, F2=32.5 N, F3=32.5 N, F4=22.8 N, and d=4.60 cm. What is the net torque about the axle?

## Homework Equations

Torque = F r sin (angle)

F = m g

## The Attempt at a Solution

I found all the torques acting on the center, disregarded T1 because its sort of passing through the center and isn't really shown on the diagram.

T1 = 0

T2= (32.5)(0.196) = 6.37 Nm

T3= -(32.5)(sin 45)(0.046)= -1.057 Nm (counterclockwise)

T4= (22.8)(0.046)= -1.0488 (counterclockwise)

Tnet = 4.26 Nm

This isn't the right answer, can someone please help and explain where I am going wrong..

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