What is the nth derivative of the function f(x)= x^n/(1-x)?

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SUMMARY

The discussion focuses on finding the nth derivative of the function f(x) = x^n / (1 - x). The initial attempt at the solution yielded the first derivative as nx^(n-1)(1-x) - x^n(-1) / (1-x)^2. Participants emphasized the importance of deriving a general formula by observing patterns through the first few derivatives. The series expansion of 1/(1-x) was suggested as a useful tool for identifying these patterns.

PREREQUISITES
  • Understanding of calculus, specifically differentiation techniques.
  • Familiarity with the concept of derivatives and their notation.
  • Knowledge of series expansions, particularly geometric series.
  • Experience with mathematical induction for proving formulas.
NEXT STEPS
  • Explore the method of finding derivatives using the Leibniz rule.
  • Study the geometric series and its application in calculus.
  • Learn about mathematical induction and how to apply it to prove formulas.
  • Investigate Taylor series and their relevance in deriving functions.
USEFUL FOR

Students studying calculus, mathematicians interested in derivatives, and educators looking for methods to teach nth derivatives effectively.

jasonbob
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Homework Statement



Find the nth derivative of the function f(x)= x^n/(1-x)

Homework Equations





The Attempt at a Solution



I got nx^n-1*(1-x)-x^n(-1) all over (1-x)^2

Is this correct and if so is their any steps afterwards?
 
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jasonbob said:
Find the nth derivative of the function f(x)= x^n/(1-x)


You only found the first derivative. Did you state the problem correctly?
 
Yes its stated properly. I realized I must have misunderstood it and did not approach that the right way
 
Are you only supposed to discover the formula or must you prove the formula that you discover by using induction?
 
It just says find the nth derivative so I assume just find the formula.
 
For this type of problem, just take a few derivatives and find the pattern. You'll be able to see what it is after taking 3 or 4 of them.
 
Perhaps, you can utilize

[tex]\frac{1}{1- x} = 1 + x + x^2 + x^3 + x^4 + ...[/tex]
 

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