What Is the Orbital Period of a Satellite Between Earth and Mars?

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SUMMARY

The orbital period of a satellite located between the orbits of Earth and Mars can be calculated using Kepler's Third Law, which states that the ratio of the cube of the semi-major axis (R) to the square of the orbital period (T) is constant for all objects orbiting the Sun. For this specific case, with a mean distance of 2.00 x 1011 m, the equation R3/T2 = 3.35 x 1018 m3/s2 applies. By rearranging the formula to solve for T, one can determine the satellite's orbital period. The semi-major axis must be accurately defined, and the ellipticity of the satellite's orbit may also be considered for precise calculations.

PREREQUISITES
  • Understanding of Kepler's Laws of planetary motion
  • Familiarity with orbital mechanics and gravitational equations
  • Knowledge of the mean distances of Earth and Mars from the Sun
  • Basic algebra for rearranging equations
NEXT STEPS
  • Calculate the orbital period using the formula R3/T2 with specific values for R between Earth and Mars
  • Research the semi-major axis and ellipticity of satellite orbits
  • Explore the implications of varying orbital distances on satellite stability
  • Learn about the gravitational influences of other celestial bodies on satellite orbits
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Astronomy students, physics enthusiasts, and aerospace engineers interested in satellite dynamics and orbital mechanics will benefit from this discussion.

sarahhhh
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Homework Statement


What would be the period of a satellite moving around the sun between the orbits of the Earth adn Mars at a mean distance of 2.00 x 10^11 m?


Homework Equations


R^3/T^2 = 3.35 x 10^18 m^3/s^2 for all objects orbiting the sun.


The Attempt at a Solution


I am so confused how to solve this problem. I set it up like this so far but I am really not sure what to do next/how to start solving the problem. http://img65.imageshack.us/img65/8821/keplerslawas4.png
 
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please help me! :(
 
I think you are slightly over reading the question.

Keplers (3rd) law just says that R^3 is proportional to T^2

We know for earth. R = 149.6 million km (you have to look this up)
T = 1 year or 365 days or 31 million seconds

so R_earth^3 / T_earth^2 = R_sat^3 / T_sat^2
Rearrange for T_sat and put the numbers in.

The bit about Mars just says that the satelite is between Earth and mars.
You can also do the above equation for Mars if you happen to know the radius of mar's orbit and the length of it's year.

If you want to split hairs it's the semi-major axis of the orbit so you would also have to know the ellipticity of the satelite.
 

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