What Is the Oscillation Frequency in an LRC Circuit?

Click For Summary
SUMMARY

The oscillation frequency in an LRC circuit with C = 13.0nF, L = 27.0mH, and R = 80.0Ω is calculated to be 8490 Hz. The critical resistance for a critically damped circuit is determined to be 2880 Ohms. To find the time it takes for the amplitude of oscillation to decay to 10.0% of its original value, the equation i = I_0e^(-((R/L)t)) is essential, as it describes the decay of maximum current due to resistance. Understanding the Q factor of the circuit is also crucial for analyzing energy loss and oscillation behavior.

PREREQUISITES
  • Understanding of LRC circuit dynamics
  • Familiarity with Kirchhoff's Laws
  • Knowledge of exponential decay functions
  • Concept of the Q factor in oscillatory systems
NEXT STEPS
  • Learn how to derive the differential equation for an underdamped LRC circuit
  • Study the relationship between Q factor and oscillation amplitude decay
  • Explore the implications of damping in RLC circuits
  • Investigate the effects of varying resistance on oscillation frequency
USEFUL FOR

Electrical engineers, physics students, and anyone studying circuit dynamics and oscillatory systems will benefit from this discussion.

Yosty22
Messages
182
Reaction score
4

Homework Statement



(image attached)

For the circuit of Fig.30.17 in the textbook, let C = 13.0nF , L = 27.0mH , and R = 80.0Ω .

A). Calculate the oscillation frequency of the circuit once the capacitor has been charged and the switch has been connected to point a

B). How long will it take for the amplitude of the oscillation to decay to 10.0% of its original value?

C). What value of R would result in a critically damped circuit?

Homework Equations





The Attempt at a Solution



I was able to get part A and part C, but I am having a really hard time with B. For A, i got 8490 Hz and for C i got 2880 Ohms. I was able to understand those very well, but I cannot figure out B at all. I have no idea how to relate any of this information to the amplitude.

Any help would be greatly appreciated.

Thanks in advanced.
 

Attachments

  • Circuit Diagram.jpg
    Circuit Diagram.jpg
    9.5 KB · Views: 1,203
Physics news on Phys.org
Investigate the Q of the circuit, and what Q represents.
 
I'm not sure, but I am still lost. My professor told me the equation

i=I_0e^-((R/L)t)

could be useful, but I cannot see how at all. I am really lost on this.
 
Yosty22 said:
I'm not sure, but I am still lost. My professor told me the equation

i=I_0e^-((R/L)t)

could be useful, but I cannot see how at all. I am really lost on this.

Yes, that equation could help as it describes the decay of the maximum current in the oscillations due to energy dissipation in the resistance. It's the "envelope" of the sinusoidal current waveform.

I was thinking of using the Q of the circuit to find the number of cycles until the energy loss brought the amplitude down to the desired level. But if you can make use of the given equation, go for it!
But I think you'll find that the damping factor should be ##\frac{R}{2L}##.

If you look in your text, or notes, you should find the solution for the underdamped case to be a sinusoid multiplied by a decaying exponential...
 
The formula for i(t) is valid for L=0 only. Here you need to derive the differential equation for the Circuit from Kirchhoff's Laws and then solve for it. As already said, this means to analyze how Q on one capacitor plate behaves with time.
 
vanhees71 said:
The formula for i(t) is valid for L=0 only. Here you need to derive the differential equation for the Circuit from Kirchhoff's Laws and then solve for it. As already said, this means to analyze how Q on one capacitor plate behaves with time.

If i(t) is interpreted as the envelope of the decaying sinusoidal current, then it should apply. Note that Io here is not the actual current at t=0 which, due to the presence of the inductor, will be zero. It's a current magnitude that you'd find if the initial energy was all in the inductor rather than in the capacitor.

If you solve the differential equation for this underdamped case it will have the form:
$$I(t) = I_o e^{-\alpha t} sin(ω_d t)$$
where ##I_o## and ##\alpha## depend upon the component values. It's that leading exponential term and constant that define the envelope. I suspect that this was the OP's professor's intention when suggesting that equation.
 

Similar threads

  • · Replies 21 ·
Replies
21
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
4
Views
3K