What is the oxidation number of platinum in Pt(NH3)2Cl(NO2)?

[Denver Dang]

Homework Statement

Hello...

Seems like an easy question, but I'm notquite sure though.

Find the oxidation number of platinum in the following compound:

Pt(NH₃)₂Cl(NO₂)

Homework Equations

The Attempt at a Solution

If I just put Pt = x, and I know that (NH3) is neutral = 0, and Cl = -1, the one thing that is bothering me is the (NO2). If it was alone, you will know that N had oxidation number +4. But here it is in another compound. Usually O is -2 and N is -3, but that gives me a total of -7 for that, and with the Cl = -1, I have a total of +8 for Pt, which I'm pretty sure is incorrect.
What am I missing ? :)Regards

 

[chemisttree]

Homework Statement

Hello...

Seems like an easy question, but I'm notquite sure though. Find the oxidation number of platinum in the following compound:

Pt(NH₃)₂Cl(NO₂)

Homework Equations

The Attempt at a Solution

If I just put Pt = x, and I know that (NH3) is neutral = 0, and Cl = -1, the one thing that is bothering me is the (NO2). If it was alone, you will know that N had oxidation number +4. But here it is in another compound. Usually O is -2 and N is -3, but that gives me a total of -7 for that, and with the Cl = -1, I have a total of +8 for Pt, which I'm pretty sure is incorrect.
What am I missing ? :)

Regards

NO2 is the nitrite anion.

 

[Denver Dang]

Of course :/

So simple.

Thank you :)