What is the p.d.f. of the sum of two normal distributions?

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SUMMARY

The probability density function (p.d.f.) of the sum of two independent normal distributions, X1 ∼ N(μ1, σ1²) and X2 ∼ N(μ2, σ2²), results in another normal distribution Y = X1 + X2. The mean of Y is calculated as μY = μ1 + μ2, while the variance is σY² = σ1² + σ2². This conclusion is derived from the moment-generating functions (MGFs) of the individual distributions, which combine multiplicatively. Therefore, Y follows the distribution N(μ1 + μ2, σ1² + σ2²).

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Homework Statement



X1 ∼ N(μ112) and X2 ∼ N(μ222)

Let Y = X1 + X2

Find the p.d.f. of Y & label the distribution.

Homework Equations





The Attempt at a Solution



Not quite sure how to go about this problem.

µY=E[Y]=E[X1+X2]=E[X1]+E[X2]=µ12

σY2=E[Y2] - µY2

E[X12+ 2X1X2 +X22] - (µ12)2

I think that might be how you start it. Feel free to correct me and start over or continue. Thanks.
 
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It's kind of hard to make suggestions without knowing more about what you know. What do you know about sums of random variables?
 
thesandbox said:

Homework Statement



X1 ∼ N(μ112) and X2 ∼ N(μ222)

Let Y = X1 + X2

Find the p.d.f. of Y & label the distribution.

Homework Equations





The Attempt at a Solution



Not quite sure how to go about this problem.

µY=E[Y]=E[X1+X2]=E[X1]+E[X2]=µ12

σY2=E[Y2] - µY2

E[X12+ 2X1X2 +X22] - (µ12)2

I think that might be how you start it. Feel free to correct me and start over or continue. Thanks.


Figured it out. The above doesn't account for all moments (rth)

MX1 + X2 = MX1(t)⋅MX2(t)

MXi=e\muit + (1/2)σi2t2

Following N~(\mu1 + \mu2 , σ12 + σ22)
 
Last edited:

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