What is the phase of the simple harmonic motion at t = 10.0 s?

[MrAlt]

Homework Statement

The function x = (2.0 m) cos[(6π rad/s)t + π/2 rad] gives the simple harmonic motion of a body. Find the following values at t = 10.0 s.

I am having trouble finding the phase of the motion, The book gives an answer of 190 rad, I am not sure how they got that

Homework Equations

V(t) = -12$\pi$Sin(6$\pi$t+($\pi$/2))
a(t) = -12$\pi$(6$\pi$)Cos(6$\pi$t+($\pi$/2))

The Attempt at a Solution

The displacement and acceleration are zero, but for some reason when i plug them into my calculator (it is set to radians) i keep getting answers other than zero, any suggestions?

 

[MrAlt]

Just found out what i was missing, and feel like a complete fool, sorry to bother you all with this, Thank You