What is the potential difference between the plates?

Click For Summary
SUMMARY

The discussion centers on calculating the potential difference between the plates of a parallel-plate air capacitor with a capacitance of 730 picoFarads and a charge of 2.95 microCoulombs. The correct potential difference is determined using the formula V=Q/C, yielding a value of 4041.1 volts. When the separation between the plates is tripled, the potential difference increases to 12123.3 volts. The work required to triple the separation can be calculated using the formula U=1/2 Q V.

PREREQUISITES
  • Understanding of capacitor fundamentals
  • Familiarity with the formula V=Q/C
  • Knowledge of energy stored in capacitors (U=1/2 Q V)
  • Basic arithmetic and algebra skills
NEXT STEPS
  • Study the principles of capacitance and its calculation
  • Learn about the effects of plate separation on capacitance
  • Explore energy storage in capacitors and related formulas
  • Investigate practical applications of capacitors in circuits
USEFUL FOR

Students and professionals in electrical engineering, physics enthusiasts, and anyone involved in circuit design or capacitor applications will benefit from this discussion.

eku_girl83
Messages
89
Reaction score
0
Here's my problem:
A parallel-plate air capacitor has a capacitance of 730 picoFarads. The charge on each plate is 2.95 microCoulombs.
a) What is the potential difference between the plates? I used the equation V=Q/C to get 2.4746E-4 V, but this is incorrect.
b)If the charge is kept constant, what will be the potential difference between the plates if the separation is tripled?
I think it would be divided by three.
c) How much work is required to triple the separation?
U=1/2 Q V

I think if I could calculate the potential difference correctly, I could work the rest of the problem. Any hints/help would be welcome!
 
Physics news on Phys.org
Check your arithmetic, I do not get the result you posted using the same equation and numbers. Post your calculation.
 
I punched the numbers into the calculator wrong! I now get the voltage equal to 4041.1
Tripling the distance produces a voltage of 3V or 12123.3
Now, how do I apply the equation U=1/2 Q V to find the work required to triple the separation?
 
it would be Uf-Ui=W
 
Thank you! You are all so helpful :)
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
7
Views
3K