I don't think so. It's probably easier to work with the mm units that were given.Abel I Daniel said:Homework Statement
8 Charged drops of water each of radius 1 mm and having a charge of 10^(-10) Coloumbs are combined to form a bigger drop.Determine the potential of the bigger drop.
Homework Equations
Does the radius becomes 4*10^(-3)m,when it combines?
Abel I Daniel said:Does the charge sum up to 9*10^(-10)?The Attempt at a Solution
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Used the formula -V=9*10^(9)*Q/r
Got the ans as 1800 V.
Mark44 said:I don't think so. It's probably easier to work with the mm units that were given.
What's the volume of one rain drop?
If you combine 8 rain drops into one bigger drop, what is the volume of this larger drop? What's its radius?
Or more simply, 4/3 ##\pi##, the volume of one rain drop,Abel I Daniel said:I assume the volume to be (4/3)*(pi)*r^3,where r is 1 mm.
From the formula you wrote in post #1, the potential V is a function of the radius r.Abel I Daniel said:But what potential has to do with Volume.i am quit weak in this subject
If 8 rain drops combine into one larger drop, what's the volume of the larger rain drop? What's the radius of the larger rain drop?-V=9*10^(9)*Q/r
i hope it adds up linearliy,that means ,radius of larger frop =8* 1mm (radius of each smaller drop)Mark44 said:If 8 rain drops combine into one larger drop, what's the volume of the larger rain drop? What's the radius of the larger rain drop?
No, it doesn't.Abel I Daniel said:i hope it adds up linearliy,that means ,radius of larger frop =8* 1mm (radius of each smaller drop)
the bigger radius becomes twice the smaller radius ie 2 mm.But what about the charge ?Mark44 said:The volumes add like you think they would, but the radius of the combined raindrop is NOT 8mm.