What is the power factor in a series circuit?

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hidemi
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Homework Statement
A series circuit consists of a 15-Ω resistor, a 25-mH inductor, and a 35-μF capacitor. If the frequency is 100 Hz the power factor is:

The answer is 0.45
Relevant Equations
PR / Pavg = Irms^2 * R / Irms^2*Z
I calculated in the following and got the correct answer. However, I wonder whether this way is correct or not. Thanks!

PR / Pavg = Irms^2 * R / Irms^2*Z = 15 /33.36 = 0.45
 
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Hi,

hidemi said:
and got the correct answer
So how did you get the 33.36 ? From 15/0.45 ? Then the answer is per se correct, but 'the way' is not :wink:

And you have me wondering why you type 33.36 and not 33.33 :cool:

##\ ##
 
BvU said:
Hi,

So how did you get the 33.36 ? From 15/0.45 ? Then the answer is per se correct, but 'the way' is not :wink:(15^2

And you have me wondering why you type 33.36 and not 33.33 :cool:

##\ ##
z=√[15^2 + (100*2π*25*10^-3 - 1/(100*2π*35*10^-6))^2]
BvU said:
Hi,

So how did you get the 33.36 ? From 15/0.45 ? Then the answer is per se correct, but 'the way' is not :wink:

And you have me wondering why you type 33.36 and not 33.33 :cool:

##\ ##
My detailed calculation is as attached.
 

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Delta2 said:
Yes the power factor is ##\cos\phi=\frac{R}{Z}##.
Ok Thank you, I understand.