**1. Homework Statement**

Find power of signal A u(t)

A is constant like 5, 6 some value.

Find power of signal A u(t)

A is constant like 5, 6 some value.

**2. Homework Equations**

Power is integration over -T/2 to +T/2 of [x(t)]

^{2}dt

The whole divide by T

**3. The Attempt at a Solution**

Power is integration over -T/2 to +T/2 of [A u(t)]

Power is integration over -T/2 to +T/2 of [A u(t)]

^{2}dtThe whole divide by T

So 1/T integral A

^{2}dt...integral limits are -T/2 to +T/2

This comes as 1/T A

^{2}integral dt

integral dt is t. limits are -T/2 to +T/2

so integral dt = [T/2 - ( -T/2) ] which becomes T

so Poewr is 1/T * A

^{2}* T

which gives A

^{2}

But book answer is A

^{2}/2

Where did the divide by 2 come from?