What is the power output in kW for this measurement?

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SUMMARY

The power output calculated from the watt-hour meter measurement is approximately 0.6164 kW. This is derived from the formula: (1 kWh)/(400 revs) * (10 revs/146 s) * 3600 s/h. The discussion clarifies that the unit kWh represents energy, which is the product of power (kW) and time (hours), confirming the conversion of kW to kJ. The correct interpretation of the time for 10 revolutions is crucial for accurate calculations.

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Homework Statement


We used a watt-hour meter in a lab, 400 revolutions of the dial = 1kWh. We measured the time for 10 revolutions of the dial ( in seconds).
How would I calculate the power?

Time for 10 revs = 146s

Homework Equations


The Attempt at a Solution


Power = (3600s/hr) / (146s) * (10/400) *1kWh = 0.62069 W ?
 
Last edited:
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Does one mean Time for 10 revs = 146s or 146 revs in 10 s?
 
Sorry... fixed :)
 
... After some more thinking...I think it should be 0.62069 kW. Would this be correct?
 
Any help would be very much appreciated... :)
 
Inquiring_Mike said:
... After some more thinking...I think it should be 0.62069 kW. Would this be correct?

Yes, but I calculate 0.6164 kW.

Take (1 kWh)/(400 revs)*(10 revs/ 146 s) * 3600 s/h = ______ kW.

The unit kWh is simply power (kW) * time (hours) = energy. 1 kW-s = 1 kJ, so 1 kWh = 3600 kJ.
 

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