What is the Power Output of the Sun's Electromagnetic Waves?

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SUMMARY

The power output of the Sun's electromagnetic waves can be calculated using the formula for the surface area of a sphere multiplied by the intensity of the waves. Given that the intensity at Earth's upper atmosphere is 1.5 kW/m², which converts to 1500 W, and the radius of the Sun is 695,500,000 meters, the correct approach involves using the distance from the Sun to the Earth, approximately 150 million kilometers (1.5 x 10^11 meters). The correct power output calculation yields approximately 9.1 x 10^21 Watts.

PREREQUISITES
  • Understanding of electromagnetic wave intensity
  • Knowledge of the surface area formula for a sphere
  • Familiarity with unit conversions (kW to W)
  • Basic concepts of astronomical distances (e.g., distance from the Sun to Earth)
NEXT STEPS
  • Research the formula for calculating the surface area of a sphere in more detail
  • Learn about the electromagnetic spectrum and its properties
  • Study the concept of solar luminosity and its implications for astrophysics
  • Explore the methods for measuring solar intensity at different distances
USEFUL FOR

Astronomy students, physics enthusiasts, educators teaching about solar energy, and anyone interested in understanding the Sun's power output and its effects on Earth.

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Homework Statement



The Sun emits electromagnetic waves (including light) equally in all directions. The intensity of the waves at the Earth's upper atmosphere is 1.5 kW/m2. At what rate does the Sun emit electromagnetic waves? (In other words, what is the power output?)

The answer is supposed to be in Watts, not kW.

Homework Equations



Surface area of sphere X Intensity = Power

The Attempt at a Solution



The surface area for a sphere = 4\pir2. The radius of the sun in meters is 695,500,000 m.

The given intensity is 1.5 kW, which I converted to 1500 W.

4\pi(695500000)2(1500) = Power output
9.1e21 = Power output

But this answer is coming up as incorrect. I'm not sure how to go about this.
 
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The question gives you the power at the distance of the Earth - what do you want to use for the radius ?
 
mgb_phys said:
The question gives you the power at the distance of the Earth - what do you want to use for the radius ?

I already tried to radius of the sun, so the radius of the Earth perhaps?

The radius of the Earth = (6,378,100 meters).
 
You have a lightbulb at the centre of a sphere - you are working out the power at the edge of the sphere.

Now picture the solar system; the sun is at the centre - at what distance is the earth?
 
mgb_phys said:
You have a lightbulb at the centre of a sphere - you are working out the power at the edge of the sphere.

Now picture the solar system; the sun is at the centre - at what distance is the earth?

Would r be the distance from the sun to the earth?
 
Like maybe 150*106 km?

That might work.
 

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