What is the Probability Density Function for a Uniform Distribution on a Disc?

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SUMMARY

The probability density function (pdf) for a uniform distribution on a disc of radius 1 is defined as f_{xy} = 1/\pi for x^2 + y^2 ≤ 1 and 0 otherwise. This formulation ensures that the total probability integrates to 1, as the area of the disc is π. The uniform distribution implies that the probability of finding (x, y) in any region is proportional to the area of that region. The discussion also highlights the correct use of LaTeX formatting for mathematical expressions.

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Homework Statement



[tex]\D = \{(x,y) \in \mathbb{R}^2 | x^2 + y^2 \leq 1\}[/tex] i.e. a disc or radius 1.
Write down the pdf f_{xy} for a uniform distribution on the disc.

Homework Equations


The Attempt at a Solution



[tex]f_{xy} = \frac{(x^2 + y^2)}{\pi} \mbox{for} x^2 + y^2<br /> 0 \mbox{otherwise}[/tex]
as the area of the disc [tex]\pi[\tex] and to make it uniform you divide by [tex]\pi[\tex] so the probability integrates to 1<br /> <br /> i apologise in advance for posting the same thing twice. i don't know how to delete 1 of them[/tex][/tex]
 
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how do you get that probability density function? as the dsitribution is uniform, i think the probability of finding x&y in any region should be proportional to its area

also in line you can use itex rather than tex, [itex]f_{xy} =[/itex] and functions within use the \ back-slash whilst to close the tex use the / forward slash
 

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