- #1
Dell
- 590
- 0
we throw a dice 5 times,
what is the probability of throwing the same number exactly 3 times?
i tried using all kinds of techuniques but can't seem to get this,
if A is a given number and X is any other number
A* A* A* X* X
6* 1* 1* 5* 5 =150
150/6^5=0.0192901
but that doesn't take into account any other options, for example A*X*A*X*A, X*A*A*X*A ...
so then i thought since i can either roll a given number or not, and the possibility that i will is 1/6
X~B(5,1/6)
P(X=3)=5C3*(1/6)^3*(5/6)^2=0.03215
the correct answer is 0.19,- which makes me think my 1st attempt was correct and there are 10 options, but how do i find these options and also, why is the binomial incorrect??
what is the probability of throwing the same number exactly 3 times?
i tried using all kinds of techuniques but can't seem to get this,
if A is a given number and X is any other number
A* A* A* X* X
6* 1* 1* 5* 5 =150
150/6^5=0.0192901
but that doesn't take into account any other options, for example A*X*A*X*A, X*A*A*X*A ...
so then i thought since i can either roll a given number or not, and the possibility that i will is 1/6
X~B(5,1/6)
P(X=3)=5C3*(1/6)^3*(5/6)^2=0.03215
the correct answer is 0.19,- which makes me think my 1st attempt was correct and there are 10 options, but how do i find these options and also, why is the binomial incorrect??