What is the R/a Ratio for a 1% Deviation in Electric Field at Point x=a/2?

  • Thread starter Thread starter seto6
  • Start date Start date
  • Tags Tags
    Electric
Click For Summary
SUMMARY

The discussion centers on calculating the R/a ratio for a 1% deviation in the electric field at the point x=a/2 between two disks of radius R and separation D=a/2. The electric field is expressed as E=(n/E_o)((1- (a/2)/(((a/2)^2)+(R^2))^1/2), where n is the charge density and E_o is the permittivity of free space (8.85*10^-12). The infinite sheet approximation gives E=n/2E_o, leading to the conclusion that the ratio R/a must be determined to achieve a deviation of 1% from this infinite sheet result.

PREREQUISITES
  • Understanding of electric fields and charge density
  • Familiarity with the concept of permittivity (E_o)
  • Knowledge of mathematical manipulation of equations
  • Basic principles of electrostatics and field theory
NEXT STEPS
  • Study the derivation of electric fields between charged plates
  • Learn about the implications of the infinite sheet approximation in electrostatics
  • Explore the concept of charge density and its impact on electric fields
  • Investigate the mathematical techniques for solving ratios in physics problems
USEFUL FOR

This discussion is beneficial for physics students, electrical engineering majors, and anyone studying electrostatics, particularly those interested in the behavior of electric fields between charged plates.

seto6
Messages
248
Reaction score
0
NOT HOME WORK QUESTION (itsfrom last year exam question)

Homework Statement


electric field between two disk of radius of R and at distance D=a/2 is given by the following
n=charge density (Q/A) E_0= the constant 8.85*10^-12

E=(n/E_o)((1- (a/2)/(((a/2)^2)+(R^2))^1/2

for what value of the ratio of the plate radius to separation between the plates does the electric field at point x=a/2 deffer by 1percent from the result n/E_o for infinite sheets?
R/a=...

Homework Equations



the equation for infinite sheet is E=n/2E_o

The Attempt at a Solution


not sure how to approach this question
is it R/2a=0.01 then R/2a*0.01=50?
please can some one explain this to me!
 
Physics news on Phys.org
What the question means is that E = 0.99 n / \epsilon

or it could also be E = 1.01 n / \epsilon.

E is given in terms of a and R, so finding the ratio should not be a problem.

Are you sure, though, that it is " 1 - a/2 " in the numerator? In this case, finding the ratio would be impossible.
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
1K
Replies
11
Views
1K
  • · Replies 26 ·
Replies
26
Views
3K
Replies
4
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K