What Is the Radial Acceleration in an Olympic Hammer Throw?

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SUMMARY

The radial acceleration of the hammer in an Olympic hammer throw is calculated to be 892 m/s², based on the parameters of a 7.3 kg ball on a 1.2 m wire released from a height of 1.3 m at an angle of 24 degrees. The relevant equations used include the projectile motion equation and the formula for radial acceleration, a = v²/r. Despite attempts to derive the velocity using horizontal motion, the calculations consistently yield a radial acceleration of 955 m/s², indicating a discrepancy that requires further investigation.

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[SOLVED] circular and projectile motion

Homework Statement


In the Olympic hammer throw, contestants whirl a 7.3 kg ball on the end of a 1.2 m long wire before releasing it. Suppose the hammer is released frim a height of 1.3 m while moving in a direction 24 degrees above the horizontal. If it travels 84 m horizontally, what is its radial acceleration just before release.
The book answer is a = 892 m/s^2


Homework Equations


y = x tan theta - gx^2/2v0^2 cos^2 theta

a = v^2/r

The Attempt at a Solution



1.3 = 84 (.445) - 9.8 (84)^2/2v0^2 (.914)^2

v0^2 = 41386.8/36.1 = 1146.4

a = 1146.4/1.2 = 955 m/s^2

Even if I just use the velocity in the x direction, it does not work.
 
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The starting height is 1.3 m. The height when x=84 is 0 m
 

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