What is the Radius of a Satellite's Circular Orbit Around Earth?

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Homework Help Overview

The discussion revolves around calculating the radius of a satellite's circular orbit around Earth, given its orbital period of 22.0 hours and the mass of the Earth. The problem is situated within the context of orbital mechanics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply Kepler's third law using the formula T^2 = (4pi^2/GM) * r^3 but is unsure about their calculations. Participants question whether the period has been correctly converted to SI units and suggest that unit consistency is crucial. There are also inquiries about the accuracy of the mass of the Earth used in the calculations.

Discussion Status

The discussion is ongoing, with participants providing guidance on unit conversion and encouraging the original poster to show their work for further analysis. There is an acknowledgment of a potential error in the calculations, but no consensus has been reached on the correct approach or solution.

Contextual Notes

There is a mention of the need to convert the period from hours to seconds, as well as the importance of using SI units for consistency in calculations. The original poster's result is noted to be significantly different from expected values, indicating possible misunderstandings in the application of the formula.

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Homework Statement


A satellite is in a circular orbit around the earth. The period of the satellite is 22.0 hr. Calculate the radius of the orbit of the satellite. Data: Mass of the Earth = 5.98·1024 kg.



Homework Equations


I thought I could use...
T^2 = (4pi^2/GM) * r^3
but I am not getting the right answer, can someone give me a start on this?
 
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This is the correct formula. Did you convert the period from hours to seconds? If not, you are going to get the incorrect answer. You have to make sure everything is in SI units.
 
I also assume you mean the mass of the Earth = 5.98*10^24 kg.
 
yes I converted it to seconds and got 1.84x10^8 m, but its wrong.
 
Show your work. You made a mistake somewhere, as you should have about 40000 km had you applied the equation properly.
 

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