What is the rate of change of power?

Click For Summary
SUMMARY

The rate of change of power produced by an engine, defined by the equation P(R) = 130R / [(R+0.8)²], can be calculated using the quotient rule of differentiation. When R = 5, the derivative of P(R) with respect to R is derived as 130 / [(R+0.8)²] - 2(130R) / [(R+0.8)³]. The confusion arose from the simplification of the quotient rule, particularly regarding the power of the denominator, which is correctly simplified to the power of 3. Understanding this differentiation process is crucial for accurately calculating the rate of change of power.

PREREQUISITES
  • Understanding of calculus, specifically differentiation and the quotient rule
  • Familiarity with power equations in physics
  • Basic knowledge of algebraic manipulation
  • Ability to evaluate derivatives at specific points
NEXT STEPS
  • Study the quotient rule in calculus for differentiating rational functions
  • Learn how to apply derivatives to real-world physics problems
  • Explore more complex power equations and their derivatives
  • Practice evaluating derivatives at specific values for various functions
USEFUL FOR

Students studying calculus, physics enthusiasts, and anyone looking to deepen their understanding of differentiation in the context of power equations.

DespicableMe
Messages
40
Reaction score
0

Homework Statement



POwer P in watts, produced by an engine is P(R) = 130R / [(R+0.8)2 ] where R is resistance. What is the rate of change of power when R = 5?

Homework Equations



The Attempt at a Solution



I do not understand how the rate of change for this is

130/ ( (R+0.8)2) - 2(130R) / ((R+0.8)3)

I have tried plugging in R=5 into what I just typed above and I got the right answer. I just don't understand how they got to that equation.

One site wrote that the ROC of current with respect to resistance is 125/R2, for example, if current was 125/R

Can someone please clarify?
 
Physics news on Phys.org
Well, what you typed there is the derivative of P(R) with respect to R. I think that's what they are asking for. What are you confused about?
 
Dick said:
Well, what you typed there is the derivative of P(R) with respect to R. I think that's what they are asking for. What are you confused about?


They simplified the form of the quotient rule, so I wasn't sure why the whole thing was over the denominator to the power of 3 instead of the power of 4.

When I did the quotient rule again, I understood where I went wrong and how they simplified it, so I have the answer now. Thanks.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
8K
Replies
8
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K