What is the Relationship Between Net Flux and Total Charge for a Cube?

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Homework Help Overview

The discussion revolves around the relationship between net flux and total charge for a cube, specifically in the context of Gauss's Law. Participants are exploring when the net flux is zero and when it is not, as well as the implications of charge placement relative to a Gaussian surface.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conditions under which net flux is zero, questioning the role of test charges and the meaning of total charge in Gauss's Law. There is an exploration of the implications of charge placement in relation to the Gaussian surface.

Discussion Status

The discussion is ongoing, with participants providing insights and prompting further exploration of concepts. Some guidance has been offered regarding the importance of charge location relative to the Gaussian surface, but no consensus has been reached.

Contextual Notes

Participants are grappling with the definitions and implications of terms such as "total charge" and "Gaussian surface," indicating potential gaps in understanding that are being addressed through questioning.

baird.lindsay
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Homework Statement



When is the net flux for a cube 0 and when is it not?


Homework Equations



∫EdA= Q/8.85E-12

The Attempt at a Solution



if you have no test charge then the flux of a cube is zero. but if you have a test charge then the net flux is the charge divided by 8.85E-12. I just want to make sure I am thinking about this correctly.
 
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baird.lindsay said:

Homework Statement



When is the net flux for a cube 0 and when is it not?


Homework Equations



∫EdA= Q/8.85E-12

The Attempt at a Solution



if you have no test charge then the flux of a cube is zero. but if you have a test charge then the net flux is the charge divided by 8.85E-12. I just want to make sure I am thinking about this correctly.
It has nothing to do with a test charge.

What does the Q represent in Gauss's Law? ##\displaystyle\ \int \vec{E}\cdot\vec{dA}=\frac{Q}{\varepsilon_0} \ ? ##
 
Q is the total charge...
 
baird.lindsay said:
Q is the total charge...
The total charge of what? ... Where is this charge located?
 
So far you are on the right track... Just think about where the charge is in relation to your Gaussian Surface. It's very important that you understand this!
 
Look closely at the form of the Equation:


\oint\vec{E}\cdot\vec{dA}


What are the implications of the closed integral?
 
SammyS said:
The total charge of what? ... Where is this charge located?

Q is the total charge enclosed by the surface. its located in the center of the surface...Im not sure I understand.
 

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