What is the relationship between temperature and pressure in gas laws?

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SUMMARY

The relationship between temperature and pressure in gas laws is governed by the ideal gas law, represented as PV = nRT. In a scenario with two rigid containers of different volumes, when the temperature is increased equally by 50 degrees, the pressure inside both containers remains the same. This is because the number of gas molecules is proportional to the volume, and the increase in temperature affects the pressure equally in both cases. Therefore, the final pressure in both containers will be identical, confirming the principles of gas behavior under constant conditions.

PREREQUISITES
  • Understanding of the ideal gas law (PV = nRT)
  • Basic knowledge of pressure, volume, and temperature relationships
  • Familiarity with rigid container properties
  • Concept of gas behavior under thermal changes
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  • Explore the effects of varying gas quantities on pressure and temperature
  • Investigate the behavior of gases in non-rigid containers
  • Learn about advanced gas laws, such as Van der Waals equation
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Ryder S
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Hi all...!

Gas laws.

Sorry about the simplicity of the question, but that should make it easy :)

I have two rigid containers open to air. One is 10 times the volume of the other.

I cap each.

I increase the temperature of each, 50 degrees.

What can I say about the pressure inside the containers, compared to each other?

A brief explanation?

Thanks ever so much.
 
Last edited:
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The pressure will be the same.

Just look at the ideal gas law:

PV = nRT, here P is pressure, V is volume, n is the number of molecules and T is the temperature. R is just a constant.

Solving for P you get:

P = nRT / V

Now, right after you close the lid on each container, notice that the number of molecules in each container is directly proportional to the volume of the container. Therefore the pressure will be the same. When you increase the temperature, it is proportional to the pressure in both cases, so when you increase the temperature equally much in both containers, you increase the pressure equally much. So the end pressure is the same.
 
Thanks... this is how I see it as well... but I'm in disagreement with a PhD about it... (I'm not one, so I have less cred), so I appreciate the sanity check.

I just think of a (very tough) soap bubble in a pressure cooker.

If you add or subtract heat... he would have to believe that the bubble would change size one way or the other as you changed temperature.

Intuitively, I just couldn't see that happening. The gas would become equally more active on both sides of the bubble, so the bubble would retain its size. The only way to change the bubble size would be to add or remove gas... so even if the bubble was slowly permeable... there would be no net exchange (discounting surface tension of the bubble, of course :)
 
Last edited:
It's not quite the same problem.
The gas inside the bubble has a higher pressure than the environment, to start with.
In your OP both containers have the same initial pressure.
 
nasu said:
It's not quite the same problem.
The gas inside the bubble has a higher pressure than the environment, to start with.
In your OP both containers have the same initial pressure.

I would tend to think a bubble would be pretty close to zero gauge pressure - in other words, the same pressure as the environment.
 
That's why I said:

"discounting surface tension of the bubble, of course :)"

So there you go.

Thanks to all!
 

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