What is the relationship between voltage and resistance in parallel circuits?

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Voltage in a circuit is often compared to the "pressure" of electrons, with its behavior differing between series and parallel circuits. In series circuits, voltage drops across each resistor, resulting in varying voltage levels as current flows through. Conversely, in parallel circuits, the same voltage is maintained across each path, even though the current may differ due to varying resistances. The analogy of potential energy can further clarify this concept, as voltage can be thought of as "height," where multiple paths allow for greater current without changing the voltage. Understanding these distinctions is crucial for grasping how voltage and resistance interact in different circuit configurations.
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I am trying to understand what exactly voltage is. I have been told that it is like the "pressure" of the electrons as they flow into the circuit.

It makes sense to me that in a series circuit that voltage changes as it goes through a resistor. A resistor resists the flow of electrons, so it makes sense that voltage or "pressure" would be lower after passing through a resistor. The electrons have slowed down as they pass through the resistor so they wouldn't have as much pressure afterward.

Now, my whole understanding of voltage falls apart when I look at parallel circiuts. How can electrons flow through resistors in a parallel circuit and not have a decrease in voltage? The resistors still slow down the electrons so why isn't there a change in voltage "pressure"? It seems like the same process is happening as in a series circuit, but there are 2 or more paths that the electrons can take.

Please help me before my brain explodes! :confused:
Thanks
 
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Hologramdr said:
I am trying to understand what exactly voltage is. I have been told that it is like the "pressure" of the electrons as they flow into the circuit.

It makes sense to me that in a series circuit that voltage changes as it goes through a resistor. A resistor resists the flow of electrons, so it makes sense that voltage or "pressure" would be lower after passing through a resistor. The electrons have slowed down as they pass through the resistor so they wouldn't have as much pressure afterward.

Now, my whole understanding of voltage falls apart when I look at parallel circiuts. How can electrons flow through resistors in a parallel circuit and not have a decrease in voltage? The resistors still slow down the electrons so why isn't there a change in voltage "pressure"? It seems like the same process is happening as in a series circuit, but there are 2 or more paths that the electrons can take.

Please help me before my brain explodes! :confused:
Thanks
In a parallel circuit, there is STILL a voltage drop, it just occurs on EACH of the separate parallel paths and is the SAME for each parallel path.

With series resistors, voltage drops in stages when the current flows thru each separate resistor. In general, the voltage drop will be different across each separate resistor. However, with a series circuit, the current is the same in each resistor.

For a parallel circuit, the same voltage is simultaneously presented to each parallel path. For a parallel circuit, voltage drop is the SAME for each separate parallel path. However, in general, the current thru each separate path will be different.

So here's a summary:
SERIES RESISTORS ---> Current the same thru each resistor; voltage drop (generally) different across each separate resistor.
PARALLEL RESISTORS ---> Voltage drop the same across each separate parallel path; current (generally) different in each separate path.


~~
 
It appears that you do understand voltage. Add to the "pressure" analogy the fact that potential is the "energy per unit of charge" (a volt is a "joule per coulomb"). So at a high potential each charge has more energy.

It is NOT good to think of this energy in the form of speed, since electrons are not "slowed down" by the resistor. Think of them as being more tightly packed together before the resistor and less tighly packed after the resistor.
 
Think of voltage as "height" (it's really a potential energy but "height" gives the same idea since potential energy is mgh). If you have water coming through a pipe down from a height, the speed of the water, and, so, the amount of water flowing through the pipe ("current") will depend upon the height. "Resistance" is the friction in the pipe that slows down the water. If you have several pipes (parallel paths) then you will have more water through those pipes (higher current) but the same "height" and so the same voltage.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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