What is the relative velocity of the two reference frames?

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SUMMARY

The discussion focuses on calculating the relative velocity between two reference frames for a particle with an energy of 5 GeV and momentum of 3 GeV. The relative velocity is determined to be 0.6c using the formula v = (pc^2)/E. Additionally, the rest mass of the particle is calculated to be 8.88 x 10^-27 kg using the equation m = E/c^2. The relativistic momentum conservation law is also referenced for further calculations.

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Homework Statement


A particle as observed in a certain reference frame has energy 5GeV and momentum 3GeV. what is the energy in a frame in which its momentum is equal to 4GeV/c?
what is its rest mass?
what is the relative velocity of the two reference frames?

Homework Equations


The Attempt at a Solution


v=(pc^2)/e
v=0.6c which is the relative velocity of the 2 frames

at v=0
e=mc^2
therefore m=e/m^2=8.88*10^-27 which is the rest mass of the particle
 
Last edited:
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I would use the relativistic momentum conservation law
[tex]E^2/c^2 + \vec{p}^2 = m^2 c^2[/tex]
in both frames. Afterwards you could use your formula to calculate the relative velocity of those two frames.
 
Last edited:

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