What is the required work to pump water out of a spherical tank?

[RedBarchetta]

[SOLVED] Work: Spherical Problem

Homework Statement

A tank is full of water. Find the work W required to pump the water out of the spout. (Use 9.8 for g and 3.14 for [PLAIN]http://www.webassign.net/images/pi.gif.[/URL] Round your answer to three significant digits.) W=_________

r=3
h=1

The Attempt at a Solution

To set up this problem, I started by taking the area of one slice of water to be pi r^{2} multiplied by an infitesimally small height \Delta y to get volume. Then multiply this by the density of water; 1000 kg/m^{3} to get the volume of one slice.

Now I want R as a function of, let's say y. We know the area of a circle is r^{2}2+y^{2}=3^{2}. So r=sqrt(9-y^{2}). Also, the distance for any slice from the top is 7-y.

After this I tried integrating from zero to six of the function 1000*pi*(9-y^{2})*(7-y)*y. This came out to be negative...in fact -36000*pi..

Apparently, that is wrong. Where did I go wrong?

Thanks.

 

[dx]

Your expression for R as a function of y is wrong.

 

[RedBarchetta]

The above equation was really meant to be r^{2}+y^{2}=3^{2}. I just noticed the typo. Or, are you saying that's wrong?

 

[HallsofIvy]

Be careful about what y represents. r= \sqrt{9- y^2} is correct if is the height above the center of the sphere. But in that case, integrating from 0 to 6 is wrong. Integrating from the bottom of the tank to the top takes y from -3 to 3.

 

[RedBarchetta]

I integrated and got 2469600*pi as my answer. My homework checker told me I was wrong. I even rounded to the proper amount of sig figs(3).

Heres what I have:
dA=(9-y^{2})pi
(Multiplied by infitesimally thickness dy)
dV=(9-y^{2})pi dy
(Since d=mv, I multiplied density of water (1000kg/m^{3})
dM=1000(9-y^{2})pi dy
(multiplied by gravity 9.8 m/s^{2})
dF=9800(9-y^{2})pi dy
(Now multiplied by distance (7-y))
dW=9800(9-y^{2})(7-y) dyNow I integrated dW with the limits from -3 to 3 and got the above result. I'm lost. Thanks for the help Ivy.

 

[dx]

The distance to the top would be 7 - y if you chose y from the bottom. It appears that you have chosen y as the distance from the center.

 

[RedBarchetta]

Great! 4-y worked.

I can finally put this problem to rest. Thanks for the help everyone!