What is the resistance of the wire and its uncertainty?

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SUMMARY

The discussion focuses on calculating the resistance of a wire using Ohm's Law, where the current is measured at 1.0 ± 0.2 A and the potential difference at 8.0 ± 0.4 V. The calculated resistance is 8.0 Ω, but the total percentage uncertainty is determined to be 25%. Participants emphasize the importance of including tolerance values in the calculations rather than simply adding percentage uncertainties. The correct answer from the multiple-choice options provided is (B) (8.0 ± 0.6) Ω, which aligns with the calculated uncertainty.

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  • Understanding of Ohm's Law (R = V/I)
  • Knowledge of calculating percentage uncertainty
  • Familiarity with basic electrical measurements (current and voltage)
  • Ability to interpret tolerance values in measurements
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  • Learn advanced techniques for calculating uncertainty in measurements
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looi76
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Homework Statement


An experiment is done to measure the resistance of a wire.
The current in the wire is 1.0 \pm 0.2A and the potential difference across the wire is 8.0 \pm 0.4V.
What is the resistance of the wire and its uncertainty?

Homework Equations


-------------

The Attempt at a Solution



\frac{0.2}{1.0} \times 100 = 20\%

\frac{0.4}{8.0} \times 100 = 5\%

Total Percentage Uncertainty = 25\%

How can I get the uncertainty?
 
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looi76 said:

Homework Statement


An experiment is done to measure the resistance of a wire.
The current in the wire is 1.0 \pm 0.2A and the potential difference across the wire is 8.0 \pm 0.4V.
What is the resistance of the wire and its uncertainty?

Homework Equations


-------------

The Attempt at a Solution



\frac{0.2}{1.0} \times 100 = 20\%

\frac{0.4}{8.0} \times 100 = 5\%

Total Percentage Uncertainty = 25\%

How can I get the uncertainty?


Do you have a lab manual for your course? Sometimes they cover this in the introduction. Also, in this course, do they use calculus, or is it precalc?
 
I don't think this question need calculus! It is a multiple choice question and the choices are:
(A) (8.0 \pm 0.2)\omega
(B) (8.0 \pm 0.6)\omega
(C) (8 \pm 1)\omega
(D) (8 \pm 2)\omega
 
\omega?...I think You mean \Omega. You have been given the Voltage (V) and the Current (I). Use Ohm's law R = V/I to find the resistance. You can't add the percentages like that. Hint: You have to include the tolerance value of the Current and voltage in the formula.
 
looi76 said:
I don't think this question need calculus! It is a multiple choice question and the choices are:
(A) (8.0 \pm 0.2)\omega
(B) (8.0 \pm 0.6)\omega
(C) (8 \pm 1)\omega
(D) (8 \pm 2)\omega

Okay, which of those answers has a 25% uncertainty?
 

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