What is the resultant speed and resultant angle of the boat?

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SUMMARY

The discussion focuses on calculating the resultant speed and angle of a rowboat crossing a river with a current. The boat's average speed is 5.39 m/s, while the river flows at 2.91 m/s. To solve the problem, participants recommend visualizing the velocities as vectors and applying the Pythagorean theorem to determine the resultant speed and angle. The user successfully solved the problem after following this vector-based approach.

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  • Understanding of vector addition
  • Familiarity with Pythagorean theorem
  • Basic knowledge of free body diagrams
  • Concept of relative velocity
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Homework Statement



A rowboat starts across river. If the average speed of the boat is 5.39 m/s and the river is flowing at a speed of 2.91 m/s, what is the resultant speed and resultant angle of the boat?

i know this is super basic but i havn't done this type of problem since the beginning of the year.

Homework Equations


v=d/t


The Attempt at a Solution


vi=o m/s
0m/s=d/2.91m/s
d=0m
 
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Instead of trying to do this purely with equations set up a picture of what's going on. Lay out the respective velocities as vectors and see if you can work from there.
 


Is the boat trying to go straight across or is it just going to go straight in reference to the water?
 


Clever-Name said:
Instead of trying to do this purely with equations set up a picture of what's going on. Lay out the respective velocities as vectors and see if you can work from there.

so i drew a picture but I am not really getting what you mean by laying out the respective velocities as vectors
 


Are you familiar with free body diagrams (while usually taught using forces you can apply the same principle to velocity vectors)? Here is my interpretation of the question as a picture:
 

Attachments

  • River.jpg
    River.jpg
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These thing usually work out to Pythagorean triangles. Think of it that way and see if you can get an answer
 


mburt said:
These thing usually work out to Pythagorean triangles. Think of it that way and see if you can get an answer

thanks for the help. i got it right! :)
 

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