# What is the resultant vector electric field at the point P?

## Homework Statement

There are 3 charges, each denoted q, the first at (0,a), the second at (0,0) and finally one at (b,0). What is the resultant electric field at point P, (b,a)?

## Homework Equations

E[/B]=q/(4πεo r2) for a point charge

## The Attempt at a Solution

So I know I need to use the superposition principle and sum the fields caused by the individual charges but I'm not sure whether I need to consider the fact that their fields wont necessarily be in the same direction.

My attempt gave me
E= q/(4πεo (1/a2 + 1/b2 + 1/(a2 + b2)) in the direction the same as sqrt(a2 + b2).

Thanks for any help, I've been debating this with friends.

Related Introductory Physics Homework Help News on Phys.org
BvU
Homework Helper
2019 Award
Hello again,

You really need to make a drawing. ##\vec E## is a vector, as is ##\vec F = q\vec E##. Fields add up, so you can calculate the forces separately and then add them up. Vector-wise, as is the habit when dealing with forces !

Oh, and ##\sqrt{a^2+b^2}## has no direction! It's a number, a scalar.

Oh, and E ##\propto## 1/r2, not 1/ ( 1/r2 )