What is the resulting angular frequency of the oscillation?

Click For Summary
The discussion revolves around calculating the angular frequency of a mass-spring system with a 0.65-kg mass and a spring constant of 15 N/m. The user initially calculates the period (T) using the formula T = 2π√(m/k) but incorrectly applies the mass in the calculation. The correct period is derived from T = 2π√(0.65 kg / 15 N/m), leading to a different angular frequency (ω). The user expresses confusion about the role of mass in the equation and seeks clarification on the correct approach. Ultimately, the importance of correctly substituting values into the formula is emphasized for accurate results.
jimmyboykun
Messages
39
Reaction score
0

Homework Statement



A 0.65-kg mass is hanging from a spring with spring constant 15 N/m. Then the mass is displaced from the equilibrium by 2 cm and let go.

Homework Equations



angular frequency:ω=2∏/T

The Attempt at a Solution



I found T: 2∏sqrtm/k, 2∏sqrt0.02/15N/m= 0.229429488s

ω=2∏/0.229429488s=27.39rad/s

I got the answer wrong but the units are suppose to be in rad/s. I feel like 0.65kg plays a role in the equation, but don't know where to place it. Where exactly did I go wrong.
 
Physics news on Phys.org
jimmyboykun said:

Homework Statement



A 0.65-kg mass is hanging from a spring with spring constant 15 N/m. Then the mass is displaced from the equilibrium by 2 cm and let go.

Homework Equations



angular frequency:ω=2∏/T

The Attempt at a Solution



I found T: 2∏sqrtm/k, 2∏sqrt0.02/15N/m= 0.229429488s

ω=2∏/0.229429488s=27.39rad/s

I got the answer wrong but the units are suppose to be in rad/s. I feel like 0.65kg plays a role in the equation, but don't know where to place it. Where exactly did I go wrong.

Take a look at the formula you used to find the period, T. What are the variables involved?

(also, make use of parentheses to delineate the argument of a function like sqrt(...) so we can tell what you're taking the square root of )
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
5
Views
3K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
817
  • · Replies 3 ·
Replies
3
Views
2K
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K