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What is the resulting frequency of the oscillation?

  1. Nov 30, 2013 #1
    1. The problem statement, all variables and given/known data

    A 0.31-kg mass is hanging from a spring with spring constant 13 N/m. Then the mass is displaced from the equilibrium by 3.3 cm and let go.

    2. Relevant equations

    for frequencthy the equation would be 1/T


    3. The attempt at a solution

    to T I would use this equation 2∏sqrtm/k
    2∏sqrt0.033m/13N/m= 0.316566651s

    1/0.316566651s= 3.158892436Hz
    I got this wrong but, this is the only equation for frequency that I was taught in class. What did I do wrong.
     
  2. jcsd
  3. Nov 30, 2013 #2

    Doc Al

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    Staff: Mentor

    In the equation, 'm' stands for the mass (measured in kg); you put in the displacement (measured in meters). Fix that!
     
  4. Nov 30, 2013 #3
    ok got it, but what about the displacement? does it not play a role in the equation?
     
  5. Nov 30, 2013 #4

    Doc Al

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    Staff: Mentor

    Not in that equation, which is for the period. The period of oscillation (for SHM) does not depend on amplitude.
     
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