What is the resulting period of the oscillation?

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SUMMARY

The discussion focuses on calculating the period of oscillation for a mass-spring system, specifically a 0.16-kg mass attached to a spring with a spring constant of 14 N/m. The correct formula for the period (T) is T = 2π√(m/k). The user initially misapplied the formula by substituting the displacement (2.9 cm) instead of the mass (0.16 kg). The correct calculation yields a period of T = 0.286 seconds.

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Homework Statement



A 0.16-kg mass is hanging from a spring with spring constant 14 N/m. Then the mass is displaced from the equilibrium by 2.9 cm and let go.

Homework Equations



the period is the time for a one full cycle so the equation would be T= 2∏sqrtm/k

The Attempt at a Solution



here's what I did I 2∏sqrt0.029m/14N/m

T=0.286s

I felt like that was to simple to solve especially in physics, what is the proper way of solving this equation?
 
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jimmyboykun said:
here's what I did I 2∏sqrt0.029m/14N/m
The same error as in the other problem you posted. 'm' is the mass, not the displacement.
 

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