What is the resulting frequency of the oscillation?

AI Thread Summary
The discussion focuses on calculating the frequency of oscillation for a mass-spring system. A 0.31-kg mass is attached to a spring with a spring constant of 13 N/m and is displaced by 3.3 cm. The correct formula for the period of oscillation is T = 2π√(m/k), which yields a period of approximately 0.3166 seconds. The frequency is then calculated as the inverse of the period, resulting in approximately 3.16 Hz. It is clarified that the amplitude of displacement does not affect the period or frequency in simple harmonic motion.
jimmyboykun
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Homework Statement



A 0.31-kg mass is hanging from a spring with spring constant 13 N/m. Then the mass is displaced from the equilibrium by 3.3 cm and let go.

Homework Equations



for frequencthy the equation would be 1/T


The Attempt at a Solution



to T I would use this equation 2∏sqrtm/k
2∏sqrt0.033m/13N/m= 0.316566651s

1/0.316566651s= 3.158892436Hz
I got this wrong but, this is the only equation for frequency that I was taught in class. What did I do wrong.
 
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jimmyboykun said:
to T I would use this equation 2∏sqrtm/k
2∏sqrt0.033m/13N/m= 0.316566651s
In the equation, 'm' stands for the mass (measured in kg); you put in the displacement (measured in meters). Fix that!
 
ok got it, but what about the displacement? does it not play a role in the equation?
 
jimmyboykun said:
ok got it, but what about the displacement? does it not play a role in the equation?
Not in that equation, which is for the period. The period of oscillation (for SHM) does not depend on amplitude.
 

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