What is the role of CdTe in CdTe/HgTe/CdTe Topological insulator?

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SUMMARY

The discussion focuses on the role of Cadmium Telluride (CdTe) in the CdTe/HgTe/CdTe quantum well structure necessary for achieving a 2D mercury telluride topological insulator. It is established that CdTe is essential due to its compatible lattice structure with HgTe, which minimizes strain and enhances the quality of the quantum well. The quantum spin Hall effect cannot be achieved with freestanding mercury telluride alone, as it lacks the necessary confinement provided by a second material with a different band gap. The lattice parameters of HgTe (0.646 nm) and CdTe (0.648 nm) demonstrate their suitability for this application.

PREREQUISITES
  • Understanding of quantum well structures
  • Knowledge of topological insulators
  • Familiarity with lattice parameters and strain effects
  • Basic principles of quantum spin Hall effect
NEXT STEPS
  • Research the properties of quantum well structures in topological insulators
  • Explore alternative materials for quantum wells beyond mercury cadmium telluride
  • Investigate the effects of lattice mismatch on material quality
  • Study the mechanisms behind the quantum spin Hall effect in detail
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Researchers in condensed matter physics, materials scientists, and engineers working on topological insulators and quantum computing applications will benefit from this discussion.

dufigo
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to get a 2D mercury telluride topological insulator,
one has to construct a quantum well structure to get a bulk gap
and most people use sandwiched structure
with mercury cadmium telluride on top and the bottom. (so CdTe/HgTe/CdTe)

and my question is
can we get same or similar quantum spin hall effect
when we use other normal insulator other than mercury cadmium telluride
or can we just use freestanding mercury telluride and see the same effect?

if CdTe is necessary, what is special about using mercury cadmium telluride?
 
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dufigo said:
to get a 2D mercury telluride topological insulator,
one has to construct a quantum well structure to get a bulk gap
[...]
and my question is
can we get same or similar quantum spin hall effect
when we use other normal insulator other than mercury cadmium telluride
or can we just use freestanding mercury telluride and see the same effect?

if CdTe is necessary, what is special about using mercury cadmium telluride?

First, free mercury telluride will not work because it simply is no quantum well. You need a second material with different band gap to get the necessary confinement for creating a quantum well as you get trapping of carriers inside the material with lower band gap.

The special thing about using CdTe is simply that it works. For quantum wells you need two materials with different band gap grown on top of each other. However, if these do not have a rather similar lattice structure, you get lots of strain by lattice mismatch which significantly lowers the quality of the structure.

The lattice parameters of HgTe and CdTe are as follows (at room temperature):
HgTe 0.646 nm CdTe: 0.648 nm

So they are a really good match.
 

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