What is the role of sinh in Snell's Law?

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Homework Help Overview

The original poster is exploring the role of the hyperbolic sine function (sinh) in the context of Snell's Law, as presented in their AS level textbook. They express confusion regarding the notation and terms used in the equations related to Snell's Law.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the potential typesetting issues in the textbook, questioning the notation of terms surrounding sinh and suggesting that the original poster may have misinterpreted the symbols. Some mention the relationship between Snell's Law and complex angles or indexes of refraction, while others emphasize the introductory nature of the material.

Discussion Status

The discussion is ongoing, with participants providing insights into possible errors in the textbook's presentation and clarifying the context of Snell's Law. There is a recognition of the introductory level of the topic, and some participants suggest that the confusion stems from typesetting rather than a deeper mathematical issue.

Contextual Notes

There are indications of potential typesetting errors in the textbook, leading to confusion about the notation used in the equations. The discussion reflects a mix of introductory physics concepts and more advanced ideas regarding complex angles and refraction.

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"sinh" in Snell's Law?

Homework Statement



I'm trying to understand some equations in my AS level textbook about Snell's Law

Homework Equations



The equations are in the image below

The Attempt at a Solution



I tried reading up about sinh but I don't fully understand what it is. Also I'm not sure what the term beside sinh is. It can't be a "1" and to seems like a small letter L which comes out of nowhere?

image.png
 
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That looks like a typesetting problem. The greek letter θ corresponds to the roman letter q (try typing q in a font like Symbol). I'm not sure where the big 1 comes from, but it should be a μ. Then you recover Snell's law:
$$
\mu_1 \sin \theta_1 = \mu_2 \sin \theta_2
$$
 
I have seen a version of Snell's law where there is not just refraction taking place but also energy absorption and reflection at interfaces. They used complex indexes of refraction and complex angles! Hyperbolic sines replaced the sin() functions. Sorry I don't remember the reference, it was a good many years ago!
 
Snell's Law is equivalent to the continuity of the tangential component of the wave vector at an interface: The component of the wave vector k parallel to the surface is the same in both media. In case of an absorbing medium, k is complex. Representing the parallel component with ksinθ, Snells Law states that k1sinθ1=k2sinθ2.
If the light came from a non-absorbing medium, k1 and θ1 are real. If k2 is complex, θ2 is a complex angle, and you have the complex sine function, ##\sin(z)=\frac{\exp(iz)-\exp(-iz)}{2i}=-i \sinh(iz)## But you can avoid by computing with complex angles if you use Snell's Law in the form kparallel= ko sinθo.

ehild
 
Last edited:
From the material presented in the OP, it is clear that this is introductory level. Hyperbolic sines have nothing to do with the poster's question, and the equation doesn't make mathematical sense (in terms of notation) if one interprets sinh as a hyperbolic sine.
 
Well, never trust texts that are written with M$ Word or similar pseudo-typesetting programs. There are exceptions, but usually one has to be very careful with such texts:devil:.
 
Hmm...

Yup, this is intro level physics and I have to agree with DrClaude: This is just one weird typesetting error. Thanks for the help guys.
 

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