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What is the sample's specific heat?

  1. Apr 5, 2008 #1
    1. The problem statement, all variables and given/known data
    You are given a sample of metal and asked to determine its specific heat. You weigh the sample and find that its weight is 30.0 N. You carefully add 1.30×10^4 J of heat energy to the sample and find that its temperature rises 20.0 degrees C.

    What is the sample's specific heat?


    2. Relevant equations

    Q=mc (delta)T

    3. The attempt at a solution

    I solved for c giving:

    c=Q/(m*(delta)T)

    I converted the given degrees Celsius to Kelvin by adding 273.15, and converted the 30 Newtons to kg by dividing by 9.8 m/s^2. The resulting numbers, 293.15 was used for delta T, and 2.90 kg was used for m.

    This was my resultant value and calculation prior to plug and chug:

    1.30*10^4 J/(2.90 kg*293.15 K)

    Plug and chug gave me 14.71 J/(kg*K). But it's not the correct answer. Could anyone show me what I did wrong?
     
  2. jcsd
  3. Apr 5, 2008 #2

    hage567

    User Avatar
    Homework Helper

    293.15 K is not the change in temperature.
     
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