What Is the Self-Locking Angle for a Block on a Steel Tabletop?

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jumpyroo92
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Homework Statement


A 10kg block sits on a steel tabletop. A 3kg block sits on the first block. A string connects the top block to the table.

a) If the string makes an angle of 10 degrees with the horizontal, how much force is required to move the middle block?

b) At what angle will the block "self lock" (an infinite force is required to slide the middle block)?

u=0.7

Homework Equations



F=ma

Ffr=uFn

Fnet(first block)= Fapp-(Ffr+Ffr) ?

The Attempt at a Solution



I really have no idea.

I don't get the self lock thing at all.
 
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