What is the Significance of (I-P)(x) in Linear Algebra?

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Homework Help Overview

The discussion revolves around the significance of the expression (I - P)(x) in the context of linear algebra, specifically related to projections onto subspaces. Participants are exploring the properties of projection operators and their implications in vector spaces.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants are attempting to understand why certain properties hold for projections, such as P(xR) = xR and P(xN) = 0. Questions are raised about the meaning of (I - P)(x) and its theoretical significance, alongside requests for visual aids to clarify the concepts.

Discussion Status

The discussion is ongoing, with some participants seeking clarification on the theoretical aspects of projections and the expression (I - P)(x). There is a mix of understanding and confusion, particularly regarding the orthogonality of subspaces and the implications of the projection operator.

Contextual Notes

Some participants express uncertainty about the orthogonality of the subspaces involved and the correctness of their visual representations. There is also mention of a recommendation to consult a teacher for further clarification on projections.

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Your two questions are "Why are P(xR)= xR and P(xN)= 0?" and "what is the meaning of (I- P)(x)?".

You are projecting x onto R. That is, xR= P(x), the component of x lying along R. If some vector, y, is already pointing in the R direction, P(y)= y. If you project again, since xR is already along R, projecting again just gives you the same thing again.

As for P(xN)= 0, that is only true if N is orthogonal to R. Your picture does not make it look like that but you say "ker P= N". If xN is in ker P, then by definition of kernel, P(x)= 0. Are you sure you aren't told somewhere that R and N are orthogonal?

Finally, (I- P)x= Ix- P(x)= x-P(x). It is x, with P(x) subtracted. If you drop a perpendicular from the tip of x to R, the intersection is at the tip of R- you have a right triangle with hypotenuse x, "near side" P(x), and opposite side x- P(x). If you "follow" the path from the origin of x to its tip, then down that perpendicular (call it "y"), you get to the tip of P(x): x+ y= P(x) so y= P(x)- x= -(I- P)x: -(I- P)x and so (I-P)x is always perpendicular to R.
 
can you please make a drawing to explain this p(Xr) p(Xn)
because i can't emagine all this components
and you said aslo that's my drawing is not correct

regarding the second part i didnt understand
the theoretical part of it
why are they doing
(I- P)(x)
what is the theoretical meenig of that
 
Last edited:
If you did not understand what I said before, then I recommend you talk to your teacher. Apparently you do not understand what a "projection" is.
 
correct me if i got it wrong p is taking the parts of the given vector
which is located on R

then the the axes are supposed to be perpandicular

i still can't understand the meening of the sign:
why are they doing
(I- P)(x)
what is the theoretical meenig of that
??
 
Last edited:

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