What is the solution for f(t,t^2)?

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SUMMARY

The solution for the function f(t, t^2) where f(x, y) = x + (xy)^(1/3) is definitively calculated as 2t. By substituting t for x and t^2 for y in the original equation, the expression simplifies to f(t, t^2) = t + (t * t^2)^(1/3), which further simplifies to f(t, t^2) = t + t, resulting in 2t. This conclusion is confirmed by the participant Brendan in the forum discussion.

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brendan
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Homework Statement



Let f(x,y) = x + (xy)^1/3

Find f(t,t^2)

Homework Equations





The Attempt at a Solution



Do I just substitute the t values into the original equation?

f(x,y) = x + (xy)^1/3

f(x,y) = t+ (tt^2)^1/3

f(x,y) = t + t

f(x,y) = 2t
 
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Looks good to me.
 
Thanks
Brendan
 

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